Question
Referring to Figure 13.1 , consider a small airplane flying at an altitude of $12,000 \mathrm{ft}$. In what layer of the atmosphere is the plane flying?
Step 1
We know that 1 foot is approximately equal to 0.0003048 kilometers. So, we multiply the given altitude by this conversion factor: \[12,000 \, \text{ft} \times 0.0003048 \, \text{km/ft} = 3.6576 \, \text{km}\] Show more…
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Look again of Figure $13.1 .$ The $X-15$ was an experimental aircraft tested from 1959 to $1968 .$ One test flew to an altitude of 67 miles. What layer of the atmosphere did the $X-15$ reach?
At an altitude of 11,000 m (a typical cruising altitude for a jet airliner), the air temperature is -56.5$^\circ$C and the air density is 0.364 kg/m$^3$. What is the pressure of the atmosphere at that altitude? (Note: The temperature at this altitude is not the same as at the surface of the earth, so the calculation of Example 18.4 in Section 18.1 doesn't apply.)
Thermal Properties of Matter
Equations of State
At an altitude of $11,000 \mathrm{m}$ (a typical cruising altitude for a jet airliner), the air temperature is $-56.5^{\circ} \mathrm{C}$ and the air density is 0.364 $\mathrm{kg} / \mathrm{m}^{3} .$ What is the pressure of the atmosphere at that altitude? (Note: The temperature at this altitude is not the same as at the surface of the earth, so the calculation of Example 18.4 in Section 18.1 doesn't apply.)
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