00:01
Today we're looking at comparing electronegativities and then also bond polarity.
00:08
So i've written on the screen the different options here that we have from problems 27 and 29.
00:21
And so the first set on the left here deals with which one, or arrange these in increasing order of electronegativity.
00:31
So if we go to figure 8 .3 and look at that table there.
00:34
We're just going to order these in increasing numerical value, because those are the electronegativity displayed on that chart.
00:42
So carbon is 2 .5, nitrogen is 3 .0, and oxygen is 3 .5.
00:49
So these are already arranged in increasing order.
00:53
For b, sulfur is 2 .5, selenium is 2 .4, and chlorine is 3 .0.
01:01
So we would do selenium, sulfur, and then chlorine.
01:08
For c, silicon is 1 .8, germanium is 1 .8, and tin is 1 .8.
01:17
So these are all equal.
01:21
And then, t .o.
01:26
1 .8, sulfur, 2 .5, and germanium is 1 .8.
01:32
So we put ptlerium, germanium, and then silver.
01:41
Now to determine bond polarity, you take the two polarities that you just looked at and you take the polarities of each element and you subtract the highest from the lowest.
01:54
And so the bigger the difference, the more polar the bond.
01:57
So here we're comparing different atoms bonded to fluorine.
02:01
So fluorine is four on each of them.
02:05
And instead of doing the math three times, we can just look at which one has the smallest electronegativity...