Question
Repeat problem 50 with a load resistor of $1.2 \mathrm{k} \Omega$
Step 1
First, let's calculate the total resistance in the circuit. We have a 1.2 kΩ load resistor, and we know that the internal resistance of the battery is 0.5 Ω. So the total resistance is the sum of these two resistances: 1.2 kΩ + 0.5 Ω = 1.2 kΩ + 0.0005 kΩ = 1.2005 Show more…
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