00:01
In this question we need to find the resistance of the immersion heater.
00:06
Okay, so we are given the mass of water is 1 .5 gggy.
00:23
The operating voltage is 110 volts.
00:27
The time taken is 10 minutes and then the temperature change is 50 degrees minus 10 degrees c okay so this is equal to 40 degrees c okay so we want to find the resistance of the immersion heater and we are given the information about water okay so we'll be we need to calculate okay the heat energy needed to raise the temperature of water okay, and so this is q equals to mc delta t, mass times specific heat capacity of water times the change in temperature, okay, and then this heat energy is equal to the power, the energy delivered by the heater, okay, and then this is going to be the power of the heater times the time taken, okay? and we'll also be using p equals to v square over r to calculate our resistance.
02:01
So we have mc delta t equals to p delta t is equal to v square over r, okay, times delta t.
02:15
So we want to find the resistance.
02:19
So we rearrange we get v square times delta small t divided by mc delta t.
02:25
And so we can substitute the numbers...