00:04
Let's determine the empirical and molecular formulas of salicylic acid.
00:09
First of all, let's calculate the molar mass using the information given.
00:14
So we have 72 .4 milliliters of 0 .1 molar n -a -o -h.
00:23
So let's convert this to moles.
00:29
So moles of n -a -o -h would be equal to the malaria.
00:36
Times the volume in liters, this would be equal to .00724 moles.
00:48
And the mass of n -a -o -h would be equal to .00724 moles times the molar mass, 1 mole of n -a -o -h is 40 .0 grams.
01:02
So this would yield 02896 grams of n -a -o -h.
01:13
So we're told that 0 .2896 grams of n .a .o .h will neutralize, neutralizes one gram of the salicylic acid.
01:34
And so 40 grams neutralizes, so 40 grams of n .ao .h will neutralize.
02:16
Neutralizes 40 over 0 .2896 and this would be equal to 138 grams of the salicylic acid.
02:41
So this is our molar mass here.
02:45
Next part of this, in one gram of so the amount of carbon.
02:54
So the amount of carbon, in 1 gram salicylic acid.
03:05
We're told that we've got 2 .23 grams of co2, 44 .0 grams of co2 to 12 grams of carbon, and this would work out to 0 .608 grams of carbon.
03:23
And the percent carbon is 0 .608 grams carbon over the one gram of the acid times 100 percent, and this would work out to 60 .8 percent carbon.
03:44
Let's now calculate the amounts of hydrogen in one gram of salicylic acid, and we're told that we have 0 .39 grams of water, 18 .0 grams, 2 .0 grams of hydrogen...