00:02
Hi everyone, you know in activity series in activity series silver is present below hydrogen silver lies below hydrogen below hydrogen and therefore its cell will not dissolve therefore silver will not be dissolved in hcl, dismaline hydrochloric acid.
00:57
Then secondly, dimension 2 .55 gram of lead.
01:02
We know the reaction between lead and hcl, that is, pb plus twice hcl gives pbcl2 plus h2 is given out.
01:17
Amount of hcl are required for distribution.
01:31
Of 6 molar and the dissolution of lead is weight of lead upon atomic mass of light mass of p b into moles of hcl divided by moles of p b into moles of of hcl into divided by moles of hcl.
03:01
So, weight of pb, they have given 2 .5 grams into moles of hcl, you know, for one mole of blade you required a 2 moles of hcl into 1000 divided by amount of pv that is 20 atomy pass of pb 207 .2 into moles of pb 1 into moles of hcl in this case required is means the molarity of hcl they have given is 6 6 so that is equal to 5100 divided by 1 ,243 .2 so that is equal to 4 .1 ml therefore amount of 6 molar axial needed to dissolve 2 .55 gram of lead that is equal to 4 .1 ml 4 .1ml.
05:00
So this is the answer for second you can say second then we'll go for third you know they have given 4 .83 gram of tin so you know first reaction reaction that is s n plus 2 hcl gives essential 2 plus h2 gas is q not now amount of hcl amount of hcl that is equal to weight of tin into moles of hcl into 1000 ml of hcl divided by atomic mass of tinn into moles of tin into number of moles of hcl that is the whole that is nothing but molarity of acal.
06:42
So, weight of 10 4 .83 into number of most of acl 2 into 1000 divided by atomic mass of 18.
06:59
180 .71 into 1 into 6...