00:08
This question asks how we can synthesize this molecule from ethine.
00:13
So to start off, we need to add some carbons on either side.
00:18
So we can tell that our triple bond is right here because that's where we've got the most action on this compound.
00:23
So we need to add a methyl group on one side and a ethel group on the other.
00:27
So the way that we'll do that is starting with nah2, that'll pull off one of these hydrogens and leave us with a carbocation.
00:36
And then we'll add in an alkyl bromide.
00:39
So first we'll do methyl.
00:42
That'll give us a ch3 on there.
00:46
And then we also have to do ethyl for the other side.
00:49
So we'll do that again.
00:51
But this time with ethyl bromide.
00:55
So then we'll get all of our carbon groups on there...