Question
Show that (a) $y H_{n}(y)=n H_{n-1}(y)+\frac{1}{2} H_{n+1}(y)$,(b) $d H_{n}(y) / d y=$$2 n H_{n-1}(y)$, and $(c) d H_{n}(y) / d y=2 y H_{n}(y)-H_{n+1}(y)$
Step 1
The Hermite polynomials $H_{n}(y)$ are defined by the formula: \[H_{n}(y)=(-1)^{n} e^{y^{2}} \frac{d^{n}}{d y^{n}}\left(e^{-y^{2}}\right)\] Show more…
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