00:01
Hi, in this video we are asked to prove the following statement.
00:05
So if we have a set a1, a2 to an, they are sets such that any pair of a .i .a .j.
00:18
That is not the same set.
00:21
We have either ai is a subset of a .j.
00:26
Or a .j is a subset of ai.
00:28
This properties means that all ai are compatible or comparable in a sense that we can know, we pick two of them, we can know which one is smaller or which one is a subset of another.
00:49
We can do this for any pair we picked.
00:53
If you are familiar with the concept of partial order or total order, you will.
01:00
Recognize right away that this is a total order on on this collection of sets and then there is next statement then there is i0 here i will just name it i zero there is an integer between one and such that a of i0 so there is this spatial a that acts as the smallest subset among all of them so this a i0 will be a subset of all other a j in this in this collection so we don't know what the number is but we know they exist or we want to show that they exist okay and there are many ways to do this.
02:00
I will show one of them.
02:02
I will use the proof by suppose the contrary and find contradiction.
02:12
Okay, so to suppose the contrary, the statement here said that there exists this special i -0 that acts as the smallest, like ai0 act as the smallest subset.
02:27
So i will suppose that it doesn't exist.
02:32
When there is no such integer i -0, what happened? then it means any set in the collection that we choose cannot be the smallest element or smallest subset, right? otherwise it will be that i0 that we assume not exist so any a j can be smallest which mean there must be another another set smaller than it so there will be some other a i that is a subset of a j that we choose always and you probably can guess what this will lead to but i will just write it out anyway.
03:28
So when this follows from our assumption, what will happen? well, first consider a1...