Question
Show that if two resistors $R_{1}$ and $R_{2}$ are combined and one is much greater than the other $\left(R_{1}>>R_{2}\right) :$ (a) Their series resistance is very nearly equal to the greater resistance $R_{1}$ (b) Their parallel resistance is very nearly equal to smaller resistance $R_{2}$ .
Step 1
e., $R_{1}>>R_{2}$. For simplicity, let's assume $R_{1}=10,000 \, \Omega$ and $R_{2}=1 \, \Omega$. Show more…
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Show that if two resistors $R_{1}$ and $R_{2}$ are combined and one is much greater than the other $\left(R_{1} \gg R_{2}\right)$ their series resistance is very nearly equal to the greater resistance $R_{1}$ and (b) their parallel resistance is very nearly equal to smaller resistance $R_{2}$.
Two resistors with resistances $R_{1}$ and $R_{2}$ are connected in parallel. Demonstrate that, no matter what the actual values of $R_{1}$ and $R_{2}$ are, the equivalent resistance is always less than the smaller of the two resistances,
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