In this gauge, the magnetic field \(\mathbf{B}\) is uniform and can be expressed as \(\mathbf{B} = B \hat{z}\) in the \(z\)-direction. Therefore, the vector potential becomes:
\[
\mathbf{A} = \frac{1}{2} B (-y, x, 0) = \frac{B}{2} (-y, x, 0).
\]
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