Question
Show that $\left|(2+x)^{2}-4\right| \leq 5|x|$ if $-1<x<1 .$ Use this to show that $\lim _{x \rightarrow 0}(2+x)^{2}=4$
Step 1
We can start by simplifying the left side of the inequality: \begin{align*} \left|(2+x)^{2}-4\right| &= \left|4+4x+x^{2}-4\right| \\ &= \left|x^{2}+4x\right| \\ &= |x|\left|x+4\right|. \end{align*} Show more…
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