00:01
We are given the parametric equations of the curve, and we are given two surfaces, and we are asked to show that the curve with these parametric equations is the curve of intersection of the two surfaces.
00:16
And then, to sketch the curve.
00:21
Parametric equations for the curve are x equals sine t, y equals cosine t, and z equals sine squared t, and the two surfaces are z equals x squared.
00:35
And x squared plus y squared equals 1.
00:44
First, let's find the curve of intersection of the two surfaces.
00:52
So we have this since z is equal to x squared, and x squared plus y squared is equal to 1, we can substitute to get z is equal to 1 minus y squared.
01:12
And this is a parabola if we project onto the yz plane.
01:38
And so this is actually a parabolic parabola, and it lies on cylinder x squared plus y squared equals 1.
02:15
So recall that this is a parabolic cylinder.
02:44
This is just a regular cylinder.
03:00
So it makes sense that their intersection is going to be parabola.
03:06
And so we have that show that this is the same curve.
03:24
Notice that we have that x squared plus y squared is equal to one, and we have that z is equal to sine squared t, which is the same as x squared.
03:44
So we have the same equations and therefore the same curve of intersection.
03:52
Now to sketch a graph of this curve, we have our x, y, and z axes.
04:12
And i'll draw both the parabolic cylinder and the cylinder first.
04:19
And then i'll indicate their curve of intersections.
04:23
So the parabolic cylinder are graph in red...