Question
Show that the maximal transverse momentum for the two-body interaction $\gamma^{*} \mathrm{q} \rightarrow$ qg is given by$$\left(p_{T}^{2}\right)_{\max }=\frac{\vec{s}}{4}=Q^{2} \frac{1-z}{4 z}$$
Step 1
The incoming virtual photon has a virtuality $Q^2$, and the quark has a momentum fraction $z$ with respect to the incoming photon. The transverse momentum of the outgoing quark and gluon is denoted as $p_T$. Show more…
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