Show that the principal stresses are
$$
T_1=-p+k, \quad T_2=-p-k \quad \text { and } \quad T_3=-p
$$
It follows that
$$
\mathbf{T}=-p \mathbf{i}+k\left(\mathbf{u}_1 \otimes \mathbf{u}_1-\mathbf{u}_2 \otimes \mathbf{u}_2\right)
$$
where $\left\{\mathbf{u}_i\right\}$, with $\mathbf{u}_3=\mathbf{i}_3$, are the orthonormal principal stress axes. Let $\mathbf{t}$ and $\mathbf{s}$ be plane orthonormal vector fields such that
$$
\mathbf{u}_1=\frac{\sqrt{2}}{2}(\mathbf{s}+\mathbf{t}), \quad \mathbf{u}_2=\frac{\sqrt{2}}{2}(\mathbf{s}-\mathbf{t})
$$
Then,
$$
\mathbf{T}=-p \mathbf{i}+\tau, \quad \text { where } \tau=k(\mathbf{t} \otimes \mathbf{s}+\mathbf{s} \otimes \mathbf{t}),
$$
and this implies that $k$ is the shear stress resolved on the $\mathbf{s}, \mathbf{t}$-axes.