00:01
In this exercise, we have to show that the ratio between the compton wavelength and the debrally wavelength of an electron is given by the square root of the energy of the electron divided by mc squared, squared minus 1.
00:18
So in order to do that, i'll first write now the energy of a relativistic electron, and that's the square root of p squared, c squared, where p is the momentum of the electron, plus mc squared.
00:38
M is the mass of the electron, and mc squared is the rest energy.
00:43
Okay.
00:47
And also, remember that p is equal to h over the doubly wavelength, lambda.
00:57
And i'm going to square both sides of the energy equation.
01:00
So i have energy squared equals p squared, and that's h squared over lambda squared, times c squared, plus mc squared squared squared...