00:01
Okay, to solve the question about the total length, we only need to use the arc length formula, right? we need to use the arc length differential, or the arc length integration.
00:15
What do i mean? the length by our definition, will be just equal to some range here, let's call it omega ds.
00:23
Ds is called the arc length differentiation, right? and by the formula we learned, we know the arc length difference.
00:33
Okay, we have one times ds, but sometimes we just leave the one, because we all know we have a one here.
00:45
By the formula we've learned about the arc length differentiation, it will be the square root of dx to the power two, plus dy to the power two.
00:58
Okay, i mean, we only know the relationship of x and y, instead of the parameterized x.
01:08
I mean, for x, which is just equal to a times sin theta, we don't know the relationship between the arc length differentiation and the theta.
01:17
So the first thing for us is to go back to the original function of our ellipsoid.
01:23
Just by the parameterization, we know the original ellipsoid will be just equal to x to the power two divided by a to the power two, plus y to the power two divided by b to the power two, is equal to one.
01:45
Okay, then what do i mean by go back to the original function because only in this original function, we know what our range is, we know how to compute the omega.
02:01
And once we have this relationship, we know our x just goes, if we want to compute the length, our x just goes from minus a to a, our y just goes from minus b to b.
02:19
Now we know x is equal to a times sin theta, y is equal to b times cosine theta.
02:40
So we know once we parameterize our x and y like that, our theta just goes from, let's see, we have, just goes from zero to two pi.
03:00
If theta is in this range, we know both those two conditions are satisfied.
03:08
Now let's consider what ds is.
03:12
Ds by the definition will be just equal to square root of dx to the power two, plus dy to the power two...