00:01
To determine which one precipitates first when we add potassium fluoride, we need to calculate the fluoride concentration required for each of them to precipitate.
00:11
In the case of calcium fluoride, ksp, being 3 .2 times 10 to the negative 11, will be equal to the calcium concentration, which is 0 .035, that's its volume, multiplied by its concentration, giving us moles, divided by the new volume once we mix the two solutions.
00:32
This is the calcium concentration.
00:35
Then, multiplied by the fluoride concentration squared, when we calculate the fluoride concentration, this will be the fluoride concentration at which ksp is met, and the calcium will begin to precipitate at that, at its concentration that we calculate here.
00:52
We get 2 .7 times 10 to the negative 5 molar.
00:55
We do the same thing with barium fluoride, where the barium fluoride ksp is 1 .5 times 10 to the negative 6, we set that equal to the barium concentration, which will be its volume in liters, multiplied by its concentration, gives us the moles barium.
01:10
We then divide by the new volume, which is the 25 milliliters plus the 35 milliliters, expressed as liters, and then multiply that by fluoride squared.
01:20
That's because there's two fluorides...