In the numerator, we can factor out $2x$ from the first two terms and $-3$ from the last two terms. In the denominator, we can factor out $2x$ from the first two terms and $-3$ from the last two terms. This gives us:
$$
\frac{2x(y+1)-3(y+1)}{2x(y+2)-3(y+2)}
$$
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