Question
Simplify each expression.$$\frac{x^{3}+7 x^{2}}{x^{2}+5 x-14}$$
Step 1
The numerator can be factored by taking out a common factor of $x^{2}$, and the denominator can be factored into two binomials. $$ \frac{x^{3}+7 x^{2}}{x^{2}+5 x-14} = \frac{x^{2}(x+7)}{(x-2)(x+7)} $$ Show more…
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