00:02
All right, so here we have a snowstorm.
00:05
And the first two hours, we have one inch coming down per hour.
00:08
That's the set in black.
00:10
Then in red, we have two inches coming down per hour for those six hours between two and eight hours.
00:17
And finally, just a half inch per hour at the last hour.
00:21
And our goal is to come up with the accumulation totals and basically with time as a piecewise function.
00:28
So let's solve each of these scenarios.
00:31
Okay, so if df dt equals 1, then if i cross multiply, df equals dt.
00:38
So i'm going to integrate both sides and that will give me f equals t plus c.
00:44
We can solve for c because we know when t is zero, we don't have any snowfall.
00:50
So zero equals zero plus c, c equals zero.
00:54
So the first part of my function is just going to be f a t.
01:01
Equals t.
01:03
So down here i'm going to make the piecewise function keep track of everything as we go along.
01:09
Okay, so f a t for the first two hours, so zero less than t less than equal to two is just t.
01:19
All right, now let's go ahead and look at the heavy snow, the two inches per hour between two and eight.
01:27
I'm going to do the same thing.
01:28
I'm going to separate variables.
01:30
This time i get two dt, i'm the right integrate both sides f then is two t plus c well let's see where we're at at two hours if i plug in f a two to my first set then i get two inches so at the end of when the first part first section's done i'm at two inches so i can say that f at two equals twice t plus c solve for c and that has to equal to inches.
02:02
So therefore, c must be we have four, so c is two minus four or minus two.
02:10
So c then is minus two.
02:12
So f of t then is two t minus two.
02:17
So that goes here, two t minus two, and that's in between two and eight, eight hours.
02:26
Okay, last set, but before we do it, we are...