00:01
We're being asked to solve the equation by using the quadratic formula, which i wrote here off to the right.
00:05
So, because our equation is already set equal to zero, let's establish our a, b, and c values.
00:10
Well, for this problem, a will be equal to 1, b will be equal to negative 3, and c will be equal to 4.
00:17
So now we just need to substitute these values into our formula.
00:20
So when we do, we're going to have p equals minus negative 3 plus or minus the square root of negative 3 squared, minus 4 times 1 times 4, and this is all getting divided by 2 times 1.
00:36
Now we just need to simplify.
00:39
Well, first, we have minus negative 3, which is positive 3.
00:43
Inside the radical, we're first to have negative 3 squared, which is positive 9.
00:48
And then we have negative 4 times 1, which is negative 4, and negative 4 times 4 is negative 16.
00:55
And in denominator, 2 times 1 is just 2...