Question
Solve each equation. If an equation is an identity or a contradiction, so indicate.$$2[5(4-a)+2(a-1)]=3-a$$
Step 1
Step 1: First, distribute the numbers inside the brackets: $$ 2[5(4-a)+2(a-1)]=3-a $$ becomes $$ 2[20-5a+2a-2]=3-a $$ Show more…
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