00:01
In this problem, we're being asked to solve the given equation.
00:03
Well, to solve this, we first need to distribute, on the left -hand side, the 3 -2 -2 -2 to both the a and the negative 4.
00:10
Well, 3 -2 times a is just 3 -2a, and 3 -2 -a.
00:15
And 3 -2 times negative 4 is negative 6.
00:19
Now, on the right -hand side of the equation, we also need to distribute the 2 to both terms in the preemphasis.
00:25
So we'll have equals 2 times a, which is 2a, and 2 -2 -3, and 2 -3, is negative 6.
00:32
And i'm going to simply bring down that minus a over 2 term.
00:38
Well, we can rewrite that a over 2 as negative 1 1 half a...