0:00
Let's look at this problem.
00:01
So 2 over y plus 3 plus 3 over 5, y minus 4 equals to 5 over y plus 6.
00:11
So the first thing we want to do is we want to cancel out out the denominator.
00:19
But this one is a little bit tricky because it's hard to find a minimal common product.
00:26
Okay, so, okay.
00:30
So we just times y plus 3 times y minus 4 times y plus 6.
00:42
Okay, so we just times these three terms.
00:46
So we can cancel out all the denominator.
00:51
So 2 times y minus 4 times y plus 6 equals to 3.
00:58
Sorry, this is plus plus three times y plus plus three times y plus three times y plus six equals to five times y plus three times y minus four.
01:19
Okay, so the next step we have to do is further simplify this equation.
01:25
So 2 times y squared minus 4y plus 6y minus 24...