00:01
So question 40, question 40 from lesson 12 .2, solve each system if possible, if a system is inconsistent or if the equations are dependent, state this.
00:18
Remember, inconsistent is no solution dependent infinitely many solutions.
00:25
So number 40, r minus s plus t equals 4, r plus 2s minus t equals negative 1, and r plus s minus 3t equals negative 2.
00:44
I see that equation 1 and equation 2 have additive inverses the t variable.
00:51
So that's the first thing i'm going to do.
00:53
I'm going to add equation one and equation two together and eliminate the t.
01:00
So r plus r is 2r, negative s plus 2s is s, and a positive t and a negative t equals 0, 4 minus 1 equals 3.
01:16
So now i'm going to look at equations 2 and 3.
01:21
If i multiply equation 2 by a negative 3, i can get additive inverses on the t variable again.
01:37
So negative 3 times r is negative 3r.
01:41
Negative 3 times 2s is negative 6s.
01:47
Negative 3 times t is plus 3t and negative 3 times negative 1 is a positive 3.
01:56
And i'm going to add that to equation number three, which is r plus s minus 3t equals negative 2.
02:09
Negative 3r and r equal negative 2 r.
02:13
Negative 6 and s equal a negative 5s.
02:20
The t's cancel out.
02:22
3 minus 2 is 1...