00:01
All right, let's look at question 42.
00:06
So number 42, i'm solving.
00:11
I have r minus 3t equals a negative 11, equation number one, r plus s plus t equals 13 for equation 2, and s minus 4t equals negative 12 for equation 3.
00:31
So i think that i could actually use substitution because i have two equations that are missing a variable term and i have leading coefficients of one, meaning that the first equation can be solved for r.
00:47
I could rewrite the first equation as r equals negative 11 minus, oh sorry, plus 3t.
00:57
I could rewrite the last equation as s equals negative 12 plus 40 and then i could look at equation number two and instead of using r in equation number two i will substitute in this value and instead of using s i will substitute in this value because i've solved both r and s in terms of t.
01:28
So let's see.
01:31
The equation number two can be written as r, which is negative 11, plus 3t, plus s, which is negative 12, plus 40, plus t, and that equals 13.
01:52
So i'm just going to combine some like terms.
01:55
3t and 4t is 70 plus 1t is 8t, negative 11 and negative 12 is negative 12 is negative.
02:06
23 equals 13...