00:01
Alright, we're going to solve the following matrix.
00:02
Now this one is going to be a dependent matrix because it's not large enough to have a unique solution.
00:08
We can use a matrix to be able to write it as equations that are dependent on certain variables and values.
00:20
So let's simplify down our equation as much as we can.
00:25
So i'm going to take my second row and i'm going to add it to...
00:31
My first row twice to cancel out that number.
00:39
So 2 plus negative 2 is 0, 1 plus 2 is 3, negative 1 plus 6 is 5, 4 plus 2 is 6.
00:54
1, 1, 3, 1, 3, 1.
01:00
And then i am going to take my first row and i'm going to go 1 3.
01:13
Third of my first row, which is going to end me in a fraction of my middle one, but it will get me to other values in my other one.
01:22
So 3 divided by 3 is 1, 5 divided by 3 is 5 thirds, 6 divided by 3 is 2, and our bottom negative 1, 1, 1, 3, and 1.
01:36
So i'm going to go my second row, minus my first row.
01:41
So 0 .153rds, 2.
01:50
And negative 1, 1 minus 1 is 0 .3 minus 5 thirds...