00:01
All right, so for this one here, we can't, there's not a unique solution.
00:05
It is inconsistent.
00:07
I don't have a large enough matrix, but we can use a matrix quickly to clean it up a bit so i can actually write my dependent equations for my set notation.
00:21
Two, three, and three.
00:24
Oops, i don't know why that one wrote four instead of one.
00:27
All right, so i am going to go.
00:31
And take row 1 and subtract 4 of row 2.
00:41
So 0, 1 minus 1 plus 4 is 5, 1 minus 8 is negative 7, negative 1 minus 12 is negative 13, and 4 minus 12 is negative 8.
01:02
1, negative 1, 2, 3, and 3.
01:07
Awesome.
01:08
And then if i wanted to go one step further, i can use my second row to cancel out, my first row to cancel out my second row a bit.
01:17
So we're going to go row two plus one fifth of row one.
01:25
So it looks a little wonky, but we'll get through it.
01:29
Or how about this? let's do this first.
01:32
We'll go one fifth of row one first.
01:36
Make our life a little easier.
01:38
0 .1, negative 7, 5ths, negative 13, 5ths, negative 8, 5ths...