00:01
Okay, so now we have the m0 is in counterclockwise direction.
00:05
Therefore, this is the force diagram for wheel.
00:08
So let's take moments about 0.
00:10
Consider counterclockwise moment is positive, clockwise moment is negative.
00:14
And this will give us 360 newton 10 meter minus fb 10 .3 meter is equal 0.
00:20
So eventually you have the friction at point b is equal to 1 ,200 newton.
00:25
Therefore, the normal force at point b should be equal to fb over mule s.
00:28
And with a muus, which is the coefficient of the static friction, is equal to 0 .6...