Question
Solve the differential equation.$ 4y'' + 4y' + y = 0 $
Step 1
The characteristic equation is obtained by replacing each derivative in the differential equation by a power of $r$. So, for the given differential equation $4y'' + 4y' + y = 0$, the characteristic equation is $4r^2 + 4r + 1 = 0$. Show more…
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