Question
Solve the equation for $x$.$$8^{x}=\left(\frac{1}{32}\right)^{x-2}$$
Step 1
Notice that \(8 = 2^3\) and \(32 = 2^5\). Therefore, we can rewrite the equation as: \[ (2^3)^x = \left(\frac{1}{2^5}\right)^{x-2} \] Show more…
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