00:01
Okay, so i'm going to solve this inequality symbolically.
00:03
What does mean to solve the inequality symbolically? well, my goal is to find all the solutions of x that make this inequality true, and this is going to be specifically when i solve for x, get it on one side of the inequality, and then i could express that solution in interval notation.
00:21
An interval notation is just another way to write the solution involving parentheses and brackets.
00:27
Okay.
00:27
So i see automatically that this inequality has a fraction in it, and i don't like my fraction.
00:34
I'm multiplying by one half, same thing as dividing by two to the entire right side.
00:40
So i'm going to try to get rid of that fraction.
00:42
I'm multiplying by one half, same thing as dividing by two, so i could also multiply by the reciprocal or just multiply by two to both sides.
00:53
Right and i'm multiplying by two to the entire left side.
00:58
This will cancel two in one half.
01:00
So i'm going to get two times the quantity 2x minus three.
01:08
And then on the right, i'm just going to get x plus one.
01:11
When i multiply by two, does that flip my inequality? it does not, right? recall that my inequality flips when i multiply or divide by a negative number.
01:21
Okay.
01:22
What would you do next? i still want to get x by itself, but i have, i'm multiplying 2 by this x over here, so i'm going to distribute that first.
01:30
2 times 2x is 4x, minus 2 times 3 is 6, and the rest of my inequality just stays same.
01:39
So i'm going to get x completely by itself, so i'm going to move everything that has x to one side and everything that doesn't have x to the other.
01:45
So how do i move this x to the left side? well, i just have x...