00:01
Okay, i want to solve this inequality symbolically.
00:03
What does it mean to solve it symbolically? well, it means to perform order of operations to both sides of the inequality to eventually get x by itself.
00:12
Why do i want to get x by itself? well, i want to determine which values of x make this inequality true always, right? it's kind of like solving an equation, but i have an inequality here.
00:23
So looking at this inequality, what would you do first? well, order of operations tells us i have two, multiply it outside parentheses.
00:31
So let's distribute this two to both sides.
00:34
I'll have 2x minus 2 times 3 minus 6 plus 1 on the left side.
00:39
I can just combine like terms.
00:42
My 2x stays by itself, negative 6 plus 1 is minus 5.
00:46
And since i just dealt with the left side, nothing else changes.
00:49
So i still have my same inequality and then i'm going to bring down 3x minus 1.
00:55
Okay.
00:56
What would you do next? well, i'm going to move everything that has x to the left side and everything that doesn't have x to the other side.
01:03
So how would i move this 2x over to the other side? well, technically i'm adding the 2x...