Question
Solve the system.$$\left\{\begin{array}{l}\frac{8}{x+2}-\frac{6}{y-5}=3 \\\frac{4}{x+2}+\frac{12}{y-5}=-1\end{array}\right.$$
Step 1
So, the system of equations becomes: $$\left\{\begin{array}{l} 8A-6B=3 \\ 4A+12B=-1 \end{array}\right.$$ Show more…
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