00:01
Okay, so for this question, they want us to name these two compounds, and then they want us to find the percent mass of manganese in these compounds.
00:08
And then lastly, they want us to prove that these two compounds follow the law of multiple proportions.
00:16
Right? so, manganese has multiple oxidative states, right? so the oxidative states are plus two, plus three, plus four, and plus seven.
00:29
Right okay so the first thing we do is we find the charge on oxygen so oxygen always has a negative 2 oxidative state right so negative 2 and since we have 3 we need to multiply this by 3 that means 03 has a negative 6 charge so in order to even it out we have 2 manganese here right so that means each manganese needs to have a plus 3 charge because if each manganese has a plus 3 charge and we have two of them we get plus 6 and these two charges from the oxygen and from the manganese will cancel out right so we have it will be manganese or plus 3 so 1 2 3 oxide now for this one oxygen has a negative 2 oxidative say like always but we have 2 oxygen that means 2 times negative 2 will equal negative 4 so that means since really 1 manganese i mean this manganese must be a plus four charge to cancel out the charge from this negative four here.
01:40
So it will be manganese, room and number four oxide.
01:52
Now for the next part, they want us to find the percent composition of manganese.
01:57
So the first thing that we should do is we have to find the total atomic weight of manganese 3 oxide.
02:08
So, manganese has a molecular weight of 55, since we have two of them, we've got to multiply it by 2, plus oxygen, we have 3 multiplied by 16 since the molecular weight of oxygen is 16.
02:23
This gives us 158.
02:27
Now we do manganese, which is 55, and we have two of them divided by 158 times it by 100, and we get about 69 .62%...