Question
SSM The nuclide 198 Au, with a half-life of $2.70 \mathrm{d},$ is used in cancer therapy. What mass of this nuclide is required to producean activity of 250 $\mathrm{Ci}$ ?
Step 1
We know that 1 Curie is equal to $3.7 \times 10^{10}$ Becquerels. Therefore, the activity in Becquerels is $250 \times 3.7 \times 10^{10} = 9.25 \times 10^{12}$ Becquerels. Show more…
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The nuclide ${ }^{198} \mathrm{Au}$, with a half-life of $2.70 \mathrm{~d}$, is used in cancer therapy. What mass of this nuclide is required to produce an activity of $250 \mathrm{Ci}$ ?
The isotope $\frac{198}{79} \mathrm{Au}$ (atomic mass $=197.968 \mathrm{u}$ ) of gold has a half-life of 2.69 days and is used in cancer therapy. What mass (in grams) of this isotope is required to produce an activity of $315 \mathrm{Ci} ?$
The isotope ${ }_{79}^{198} \mathrm{Au}$ (atomic mass $=197.968 \mathrm{u}$ ) of gold has a half-life of $2.69$ days and is used in cancer therapy. What mass (in grams) of this isotope is required to produce an activity of 315 Ci?
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