Question
The nuclide ${ }^{198} \mathrm{Au}$, with a half-life of $2.70 \mathrm{~d}$, is used in cancer therapy. What mass of this nuclide is required to produce an activity of $250 \mathrm{Ci}$ ?
Step 1
We know that 1 Ci is equal to $3.7 \times 10^{10}$ Bq. So, the activity in Becquerels is: \[ A = 250 \, \text{Ci} \times 3.7 \times 10^{10} \, \text{Bq/Ci} = 9.25 \times 10^{12} \, \text{Bq} \] Show more…
Show all steps
Your feedback will help us improve your experience
Keshav Singh and 64 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
SSM The nuclide 198 Au, with a half-life of $2.70 \mathrm{d},$ is used in cancer therapy. What mass of this nuclide is required to produce an activity of 250 $\mathrm{Ci}$ ?
One of the many isotopes used in cancer treatment is $_{79}^{198} \mathrm{Au}$, with a half-life of 2.70 $\mathrm{d} .$ Determine the mass of this isotope that is required to give an activity of 225 $\mathrm{Ci} .$
The isotope ${ }_{79}^{198} \mathrm{Au}$ (atomic mass $=197.968 \mathrm{u}$ ) of gold has a half-life of $2.69$ days and is used in cancer therapy. What mass (in grams) of this isotope is required to produce an activity of 315 Ci?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD