Question
Standing waves are produced by the superposition of two waves $\mathrm{y}_{1}=0.05 \sin (3 \pi \mathrm{t}-2 \mathrm{x})$ and $\mathrm{y}_{2}=0.05 \sin (3 \pi \mathrm{t}+2 \mathrm{x})$where $\mathrm{x}$ and $\mathrm{y}$ are in meters and $\mathrm{t}$ is in seconds.The amplitude of a particle at $\mathrm{x}=0.5 \mathrm{~m}$ is $\ldots \ldots$(A) $1.08 \times 10^{-1} \mathrm{~m}$(B) $5.4 \times 10^{-2} \mathrm{~m}$(C) $(\pi / 2) \times 10^{-1} \mathrm{~m}$(D) $\pi \times 10^{-1} \mathrm{~m}$
Step 1
05 \sin (3 \pi \mathrm{t}-2 \mathrm{x})$ and $\mathrm{y}_{2}=0.05 \sin (3 \pi \mathrm{t}+2 \mathrm{x})$. These are two waves traveling in opposite directions with the same amplitude, frequency, and speed, but different wave numbers. Show more…
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Standing waves are produced by the superposition of two waves $y_{1}=0.05 \sin (3 \pi t-2 x)$ and $y_{2}=0.05 \sin (3 \pi t+2 x)$ where $\mathrm{x}$ and $\mathrm{y}$ are in meters and $\mathrm{t}$ is in seconds. The velocity (in $\mathrm{ms}^{-1}$ ) of a particle at $\mathrm{x}=0.25 \mathrm{~m}$ at $\mathrm{t}=0.5 \mathrm{~s}$ is $\ldots \ldots$ (A) $0.1 \pi$ (B) $0.3 \pi$ (C) zero (D) $0.3$
Standing waves are produced by the superposition of two waves $$ \begin{aligned} &y_{1}=0.05 \sin (3 \pi t+2 x) \\ &y_{2}=0.05 \sin (3 \pi t+2 x) \end{aligned} $$ where $x$ and $y$ are in metres and $t$ is in second. What is the amplitude of the particle at $x=0.5 \mathrm{~m} ?$. Given, $\cos 57.3^{\circ}=0.54$. (a) $2.7 \mathrm{~cm}$ (b) $5.4 \mathrm{~cm}$ (c) $8.1 \mathrm{~cm}$ (d) $10.8 \mathrm{~cm}$
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Round 2
Standing waves are produced by the superposition of two waves $y_{1}=0.05 \sin (3 \pi t-2 x)$ and $y_{2}=0.05 \sin (3 \pi t+2 x)$ where $\mathrm{x}$ and $\mathrm{y}$ are in meters and $\mathrm{t}$ is in seconds. The distance (in meters) between two consecutive nodes is (A) $\pi / 2$ (B) $\pi$ (C) $0.5$ (D) $1.0$
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