Substituting $u(x, y)=X(x) Y(y)$ into the partial differential equation yields $x X^{\prime} Y=y X Y^{\prime} .$ Separating variables and using the separation constant $-\lambda$ we obtain
$$\frac{x X^{\prime}}{X}=\frac{y Y^{\prime}}{Y}=-\lambda.$$
When $\lambda \neq 0$
$$x X^{\prime}+\lambda X=0 \quad \text { and } \quad y Y^{\prime}+\lambda Y=0$$
so that
$$X=c_{1} x^{-\lambda} \quad \text { and } \quad Y=c_{2} y^{-\lambda}.$$
A particular product solution of the partial differential equation is
$$u=X Y=c_{3}(x y)^{-\lambda}.$$
When $\lambda=0$ the differential equations become $X^{\prime}=0$ and $Y^{\prime}=0,$ so in this case $X=c_{4}, Y=c_{5},$ and $u=X Y=c_{6}.$