Question
Sulfur and fluorine form at least two compounds $-\mathrm{SF}_{4}$ and $\mathrm{SF}_{6}$. Explain how these compounds can be used as an example of the Law of Multiple Proportions.
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The Law of Multiple Proportions states that when two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other element are in the ratio of small whole numbers. Show more…
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Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a sample of sulfur hexafluoride produces 4.45 g of fluorine and 1.25 g of sulfur, while decomposition of a sample of sulfur tetrafluoride produces 4.43 g of fluorine and 1.87 g of sulfur. Calculate the mass of fluorine per gram of sulfur for each sample and show that these results are consistent with the law of multiple proportions.
Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a sample of sulfur hexafluoride produces 4.45 g of fluorine and 1.25 $\mathrm{g}$ of sulfur, while decomposition of a sample of sulfur tetrafluoride produces 4.43 g of fluorine and 1.87 g of sulfur. Calculate the mass of fluorine per gram of sulfur for each sample and show that these results are consistent with the law of multiple proportions.
Sulfur (S) and fluorine (F) form several different compounds. One of them, $\mathrm{SF}_{6}$, contains $3.55 \mathrm{g}$ of $\mathrm{F}$ for every gram of S. Use the law of multiple proportions to determine $n,$ which represents the number of F atoms in $\mathrm{SF}_{n},$ given that it contains $2.37 \mathrm{g}$ of $\mathrm{F}$ for every gram of S.
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