00:01
Okay, problem 65, first of all, you have to calculate chauffeur in 25, 25 matrix tons of coal first, and then we get the mass of the chauffeur.
00:20
We continue to do like similar problem 64.
00:23
Okay, that's a strategy.
00:26
So let me see, problem 65.
00:50
We know the server got 3%, right? so we got a 25 because we know metric ton equal 10 by 3 kilograms so you can write like this so we have this equal 2 .5 time 10 or 2 kilogram this equal this equal 2 .5 time 10 or 2 kilogram this equal this equal 2 .5 time 10 power 5 gram why i do convert to gram because in the equation we do gram -ram -ram -ram -ram now we have sulfur react with oxygen to reduce sulfur dioxide.
02:01
And now from gram or sulfur i convert to more sulfur.
02:06
And more sulfur i convert to more sulfur dioxide.
02:10
And more the sulfur dioxide will correlate the gram of sulfur dioxide.
02:15
Like the way we do for problem 49, i 64.
02:19
I think here.
02:25
Look at this one.
02:47
We have, i think, this is 7 .5.
03:38
So what do we can solve? mons here, more here, more here, more here, gram here, gram here, and then the end we get only sulfur dioxide...