Suppose some ${ }^{235} \mathrm{U}^{+}$ ions are present in the beam. They have the same charge as the ${ }^{238} \mathrm{U}^{+}$ ions but a smaller mass (approximately 0.98737m). (a) With what speed do the ${ }^{23} \mathrm{U}^{+}$ ions emerge from the accelerating plates, assuming ${ }^{238} \mathrm{U}^{+}$ ions emerge with speed $v ?$
(b) Sketch the trajectory of ${ }^{235} \mathrm{U}^{+}$ ions inside the velocity selector.
(c) Now the velocity selector is removed. ${ }^{238} \mathrm{U}^{+}$ ions move in a circular path of diameter $D$ in the uniform magnetic field. What is the diameter of the path of the ${ }^{235} \mathrm{U}^{+}$ ions?