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Suppose that $ f(5) = 1, f' (5) = 6, g(5) = -3, $ and $ g'(5) = 2. $ Find the following values.(a) $ (fg)' (5) $

(b) $ (f/g)' (5) $

(c) $ (g/f)' (5) $

(a) -16(b) -20 / 9(c) 20

02:00

Frank L.

Calculus 1 / AB

Chapter 3

Differentiation Rules

Section 2

The Product and Quotient Rules

Derivatives

Differentiation

Campbell University

University of Nottingham

Idaho State University

Boston College

Lectures

03:09

In mathematics, precalculu…

31:55

In mathematics, a function…

00:36

Let $f(x)=2 x-5$ and $g(x)…

00:32

01:10

If $ F(x) = f(g(x)), $ whe…

02:31

Given $f(x)=6 x+5$ and $g(…

00:30

05:43

If $f(x)=x+5$ and $g(x)=x^…

00:38

02:30

Let $f(x)=5 x-1$ and $g(x)…

01:09

Let $f(x)=-3 x+1$ and $g(x…

feats. Clearasil on rain here. So, for part A, we're gonna use the product rule. Let me get F G. Derivative five is equal to derivative of F five GF five less five derivative of G of five. You plug it in and you get six times negative. Three plus one times two, which is equal to negative 16. We have part being f departed by G. The derivative of five is equal to the drill bit it, uh, the five g of five minus F five. The derivative of chief of Fly all over G of five square and you get six times negative. Three minus one times two over a negative three square, giving us negative. 20 over nine For part C, you have Jeanne divided by s the derivative five, which is equal to the derivative of G of five. Yes, a five minus g of five. The derivative of F of five all over five square. This is equal to two time one minus negative. Three. I'm six over one square, which is equal to 20

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