00:01
All right, so we have here that s1 is going to be equal to one -half t -squared minus t plus three, and then we let s -2 be equal to negative one -fourth t -squared plus t -plus -1.
00:17
So for collision, we can set s -1 being equal to s -2, and then we are going to get here 3 .4 t squared minus 2t plus 2 is equal to 0.
00:35
We can multiply here by 4 to give us 3t squared minus 8t plus 8 is equal to 0.
00:43
And then the discriminant is that b squared minus 4 ac.
00:47
The discriminant here is going to be negative 8 squared minus 4 times.
00:53
3 times 8, which is equal to 64 minus 96.
00:58
That's negative 32.
01:00
Since this is negative, we could say there are no real solutions.
01:08
There are no real solutions, and therefore, p1 and p2 do not collide.
01:17
They do not collide.
01:19
And then for b, well, the closest distance between them would be.
01:24
The s1 minus s2 would be equal to 3 4 t squared minus 2 t plus 2.
01:35
This is a parabola opening upwards...