00:01
For this problem, we are told that three fair coins are tossed, and x is the square of the number of heads showing.
00:06
We are first asked to give the probability distribution for the indicated random variable.
00:12
What we'll need to do before that, though, is figure out what our sample space is.
00:17
So we have three fair coins.
00:21
The possible results would be tails, tails, tails, tails, or tails, tails, tails, tails, tails, heads, tails, heads, tails, heads, tails, then there's tails, tails heads heads heads, tails, tails, then there's tails, tails, tails, tails, tails.
00:38
Heads, heads, heads, heads, excuse me, heads, heads, heads, heads, heads, heads, and lastly, tails, or excuse me, heads, heads, heads, rather, not tails, tails, tails, going in order of the number of heads showing.
01:01
We can then see that the values of x corresponding to each would be 0, 1, 4, 4, 4, 4, or excuse me, i need to correct myself here, it is the number of heads, so it would be 0 -1 -1 -1.
01:20
Then we have 4 -4 -4, and then we have a final possibility of 9.
01:28
So our probability distribution table then have the different results.
01:33
We have the probability of each result, where i'll note that we have a total of eight different possible results.
01:41
And we have, or excuse me, not eight different possible results, but we have eight different elements.
01:48
In our sample space is what i'll say.
01:51
Then we have for the probability of getting zero, well, there's a one and eight chance of that happening...