The torque is given by the formula $\tau = F \cdot r$, where $F$ is the force and $r$ is the distance from the pivot.
For the first child, the torque is $\tau_1 = (30.0 \mathrm{~kg}) \cdot (9.8 \mathrm{~m/s^2}) \cdot (1.40 \mathrm{~m}) = 411.6 \mathrm{~N \cdot
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