00:01
So i'll keep this list of things that we have to do over here.
00:03
So x prime is going to be 2t root 3, and y prime is going to be 3 minus t squared.
00:17
So first, trying d, y, d, y, d, x, that'll be 3 minus t squared over 2t root 3.
00:25
So that's root 3 over 2t minus t over 2r3.
00:40
That's this.
00:42
Now if we take this derivative, we get root t or dt, we get root 3, root 3 over negative root 3 over 2t squared minus 1 over 2 root 3.
01:05
And if we divide that by 2t root 3, then we get d squared y over dx squared.
01:13
So that would be negative 1 over 4 t cubed minus 1 over 12 t.
01:31
So the equation of the tangent line at the point root 3, 8 thirds.
01:37
So that's at t equals 1.
01:39
So if you put t equals 1 into this equation, you have the slope will be root 3 over 2 minus 1.
01:51
I'll say root 3 every 6.
01:54
So that is root 3 over 3.
02:03
So if we put in root 3 in for x, then we get 1...