The position function given is \(\theta(t) = 10 + 90t^2 - 60t^3\). We need to find the position at \(t = 0\) and \(t = 1\).
- At \(t = 0\):
\[
\theta(0) = 10 + 90 \cdot 0^2 - 60 \cdot 0^3 = 10
\]
- At \(t = 1\):
\[
\theta(1) = 10 + 90 \cdot 1^2 - 60
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