Question
Tangents drawn to $x^{2}+y^{2}=16$ from $P(0, h)$ meet the $x$ -axis at $A$ and $B$. The value of $h$ for which the area of triangle $\mathrm{PAB}$ is minimum is(a) 32(b) $\sqrt{30}$(c) $\sqrt{31}$(d) $4 \sqrt{2}$
Step 1
The given equation is \(x^2 + y^2 = 16\), which represents a circle centered at the origin \((0, 0)\) with a radius of \(4\). Show more…
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